Let position vectors of points A, B and C of triangle ABC respectively be \(\vec{i} + \vec{j} + 2\vec{k}\), \(\vec{i} + 2\vec{j} + \vec{k}\) and \(2\vec{i} + \vec{j} + \vec{k}\). Let \(l_1\), \(l_2\) and \(l_3\) be the lengths of perpendiculars drawn from the orthocenter 'O' on the sides AB, BC and CA, then \((l_1 + l_2 + l_3)\) equals
Let a vector $\vec{a}=\sqrt{2}\hat{i}-\hat{j}+\lambda\hat{k}$, $\lambda>0$, make an obtuse angle with the vector $\vec{b}=-\lambda^2\hat{i}+4\sqrt{2}\hat{j}+4\sqrt{2}\hat{k}$ and an angle $\theta$, $\dfrac{\pi}{6}<\theta<\dfrac{\pi}{2}$, with the positive $z$-axis. If the set of all possible values of $\lambda$ is $(\alpha,\beta)-\{\gamma\}$, then $\alpha+\beta+\gamma$ is equal to ___.
Five points given by A, B, C, D and E are in a plane. Three forces $\vec{AC}$, $\vec{AD}$ and $\vec{AE}$ act at A and three forces $\vec{CB}$, $\vec{DB}$ and $\vec{EB}$ act at B. Then, their resultant is