Let $f:\mathbb{R}\to\mathbb{R}$ be a twice differentiable function such that $f''(x)>0$ for all $x\in\mathbb{R}$ and $f'(a-1)=0$, where $a$ is a real number. Let $g(x)=f(\tan^2x-2\tan x+a)$, $0<x<\dfrac{\pi}{2}$.
Consider the following two statements:
(I) $g$ is increasing in $\left(0,\dfrac{\pi}{4}\right)$
(II) $g$ is decreasing in $\left(\dfrac{\pi}{4},\dfrac{\pi}{2}\right)$. Then,
Let $f:\mathbf{R}\to\mathbf{R}$ be a twice differentiable function such that the quadratic equation $f(x)\mathrm{m}^2-2f'(x)\mathrm{m}+f''(x)=0$ in m, has two equal roots for every $x\in\mathbf{R}$. If $f(0)=1$, $f'(0)=2$, and $(\alpha,\beta)$ is the largest interval in which the function $f(\log_e x-x)$ is increasing, then $\alpha+\beta$ is equal to _____
The feasible solution for a LPP is shown in the following figure. Let \(z = 3x - 4y\) be the objective function. Minimum of \(z\) occurs atCorner points: \((0,0),\, (0,8),\, (4,10),\, (6,8),\, (6,5),\, (5,0)\)