\(P_r(x_r, y_r);\, r = 1, 2, 3, \ldots\) is a sequence of points on the curve \(y^3 = x\). The tangent at \(P_n\) cuts the curve again at \(P_{n+1}\) for all \(n \in \mathbb{N}\). Then \(y_1, y_2, y_3, \ldots\) are in
Given quadratic equation is \(ax^2 + bx + c = 0\) Let \(f'(x) = ax^2 + bx + c\), so \(f(x) = \frac{ax^3}{3} + \frac{bx^2}{2} + cx\). Clearly, \(f(0) = 0\) and \(f(1) = \frac{1}{6}(2a + 3b + 6c) = 0\). Given that \(f(0) = 0 = f(1)\), by Rolle's theorem, \(f'(x)\) has at least one root in \((0, 1)\). The root of \(ax^2 + bx + c = 0\) lies in:
Let \(f(x)\) be a differentiable function on \([0, 8]\) such that \(f(1) = 3\), \(f(2) = 1/2\), \(f(3) = 4\), \(f(4) = -2\), \(f(5) = 6\), \(f(6) = 1/3\), \(f(7) = -1/4\). Then the minimum number of points of interaction of the curve \(y = f'(x)f(x)^2\) and \(y = f'(x)f(x)^2\) is \(k\), then find \(k\).