Let $K$ be the sum of the coefficients of the odd powers of $x$ in the expansion of $(1+x)^{99}$. Let $a$ be the middle term in the expansion of $\left(2+\dfrac{1}{\sqrt{2}}\right)^{200}$. If $\dfrac{{}^{200}C_{99}\,K}{a}=\dfrac{2^\ell\,m}{n}$, where $m$ and $n$ are odd numbers, then the ordered pair $(\ell,n)$ is equal to:
Line \(L_{1}\) of slope 2 and line \(L_{2}\) of slope \(\frac{1}{2}\) intersect at the origin \(O\). In the first quadrant, \(P_{1}, P_{2}, \ldots ., P_{12}\) are 12 points on line \(L_{1}\) and \(Q_{1}\), \(Q_{2}, \ldots ., Q_{9}\) are 9 points on line \(L_{2}\). Then the total number of triangles, that can be formed having vertices at three of the 22 points \(O, P_{1}\), \(P_{2}, \ldots, P_{12}, Q_{1}, Q_{2}, \ldots ., Q_{9}\), is: