Let a circle C pass through the points (4, 2) and (0, 2), and its centre lie on 3x + 2y + 2 = 0. Then the length of the chord, of the circle C , whose mid-point is (1, 2), is :
Let circle $C$ be the image of $x^2 + y^2 - 2x + 4y - 4 = 0$ in the line $2x - 3y + 5 = 0$ and $A$ be the point on $C$ such that $OA$ is parallel to $x$-axis and $A$ lies on the right hand side of the centre $O$ of $C$. If $B(\alpha, \beta)$, with $\beta < 4$, lies on $C$ such that the length of the arc $AB$ is $\tfrac{1}{6}^{\text{th}}$ of the perimeter of $C$, then $\beta - \sqrt{3}\,\alpha$ is equal to
From the following figure, which depicts the given situation, the circle touches the line \(y = -x\). Also, from the graph, the radius is obtained as \(4 - k\). The circle passes through \((0, 4)\) and its centre is at \((0, k)\). The radius of the circle is: