Complex Numbers Questions (654)

If \( \omega \) is a primitive \(n\)th root of unity, then \( 1 + \omega + \omega^2 + \cdots + \omega^{n-1} \) equals:
The solutions of the equation z^4 + 4iz^3 - 6z^2 - 4iz - i = 0 represent vertices of a convex polygon in the complex plane. The area of the polygon is:
A rectangle of maximum area is inscribed in the circle \(|z - 3 - 4i| = 1\). If one vertex of the rectangle is \(4 + 4i\), then another adjacent vertex of this rectangle can be
For the regular hexagon ABCDEF with $z_1 = -2$ and $z_3 = 1 - \sqrt{3}i$, the square of the inradius of the hexagon is equal to
Locus of the point z satisfying the equation |iz - 1| + |z - 1| = 2, is (where i = \sqrt{-1})
Let \(z = r(\cos\theta + i\sin\theta)\). The least value of \(\dfrac{\sin 5\theta}{(\sin\theta)^5}\) expressed in terms of \(\cot\theta\) is:
Let the product of$\$omega = (8 + i)$sin$$\$theta + (7 + 4i)$cos$$\theta and$$\$omega = (1 + 8i)$sin$$\$theta + (4 + 7i)$cos$$\theta be$$\alpha + i$$\beta, 1 2 i =$$\$sqrt-1$. Let p and q be the maximum and the minimum values of$$\alpha +$$\beta respectively.$
If \(z_1\) and \(z_2\) are the complex roots of the equation \((x-3)^3 + 1 = 0\), then \(z_1 + z_2\) equals
If \(z\) is a complex number having least modulus and \(z - 2 - 2i| = 1\), then \(z =\)
Given \(\alpha, \beta\), respectively, the fifth and the fourth non-real roots of unity, respectively, then find the value of \((1 + \alpha)(1 + \beta)(1 + \alpha^2)(1 + \beta^2)(1 + \alpha^4)(1 + \beta^4)\).
If \(\dfrac{z-i}{z+i}\) is a purely imaginary number (where \(z \neq -i\)), then which of the following is true?
Find $a^{10} + \bar{a}^{10}$ where $a = \frac{2-\sqrt{-3}}{3}$
(D) $2, 3 + 2$
If \(|z_2 + iz_1| = |z_1| + |z_2|\) and \(|z_1| = 3\) and \(|z_2| = 4\), then the area of \(\triangle ABC\), if affixes of \(A\), \(B\), and \(C\) are \(z_1, z_2\), and \([(z_2 - iz_1)/(1-i)]\) respectively, is
For Problems 26–28: Complex numbers \(z\) satisfy the equation \(|z - (4/z)| = 2\).Locus of \(z\) if \(|z - z_1| = |z - z_2|\), where \(z_1\) and \(z_2\) are complex numbers with the greatest and the least moduli, is
Sum of common roots of the equations \(z^3 + 2z^2 + 2z + 1 = 0\) and \(z^{1985} + z^{100} + 1 = 0\) is
For the circle with center $\left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right)$, find the condition on $(Z-1)^n = Z^n \Rightarrow |Z-1| = |Z| \Rightarrow x = \frac{1}{2}$. Given $\frac{1}{2} + y^2 = 1 \Rightarrow y = \pm\frac{\sqrt{3}}{2}$. Which would exist when $n$ is a multiple of $6$: $\arg\left(\frac{1}{2} + \frac{\sqrt{3}}{2}i\right) = \tan^{-1}\sqrt{3} = \frac{\pi}{3}$; least value of $n$ is equal to $\frac{2\pi}{6}$
The number of points in the complex plane satisfying both $|z-2|=2$ and $z(1-i)+\bar{z}(1+i)=4$ (where $i=\sqrt{-1}$) is
One root lies inside the unit circle and one outside if
If \(a\) and \(b\) are complex and one of the roots of the equation \(x^2 + ax + b = 0\) is purely real whereas the other is purely imaginary, then
A complex number $z$ is said to be unimodular if $|z| = 1$. Let $z_1$ and $z_2$ are complex numbers such that $\frac{z_2 - z_1}{z_2 - z_3}$ is unimodular and $z_2$ is not real. Then $z_1$ lies on a
If \(|z - i\,\text{Re}(z)| = |z - \text{Im}(z)|\), then prove that \(z\) lies on the bisectors of the quadrants.
The minimum value of the expression $|3z - 3| + |2z - 4|$ is equal to (where, $z$ is a complex number)
Let \(z_1\) and \(z_2\) be two roots of the equation \(z^2 + az + b = 0\), \(z\) being complex. Further, assume that the origin, \(z_1\) and \(z_2\) form an equilateral triangle, then
The complex numbers \(\sin x + i\sin 2x\) and \(\cos x - i\cos 2x\) are conjugate to each other, for
If \(|(z - z_1)/(z - z_2)| = 3\), where \(z_1\) and \(z_2\) are fixed complex numbers and \(z\) is a variable complex number, then \(z\) lies on a
If \(\left(\dfrac{1+i}{1-i}\right)^x = 1\), then
A complex number \(z\) is said to be unimodular if \(|z| = 1\). Suppose \(z_1\) and \(z_2\) are complex numbers such that \(\dfrac{z_1 - 2z_2}{2 - z_1\bar{z}_2}\) is unimodular and \(z_2\) is non-unimodular. Then the point \(z_1\) lies on a
The largest value of \(r\) for which the region represented by the set \(\{\omega \in \mathbb{C} : |\omega - 4 - i| \leq r\}\) is contained in the region represented by the set \(\{z \in \mathbb{C} : |z - 1| \leq |z + i|\}\), is equal to
Find the locus of the points representing the complex number \(z\) for which \(|z+5|^2 - |z-5|^2 = 10\).
Find the value of \[\frac{i^{592} + i^{590} + i^{588} + i^{586} + i^{584}}{i^{582} + i^{580} + i^{578} + i^{576} + i^{574}} - 1\]
If z = x + iy, then the equation |(2z − i)/(z + 1)| = m represents a circle, then m can be
Find the greatest and the least value of \(|z_1 + z_2|\) if \(z_1 = 24 + 7i\) and \(|z_2| = 6\).
If \(|z - 2 - 3i|^2 + |z - 5 - 7i|^2 = \lambda\) represents the equation of a circle with least radius, then find the value of \(\lambda\).
For any complex number \(z\), find the minimum value of \(|z| + |z - 2i|\).
The point represented by \(2+i\) in the Argand plane moves 1 unit eastwards, then 2 units northwards and finally from there \(2\sqrt{2}\) units in the south-westwards direction. Then its new position in the Argand plane is at the point represented by
If
If 1, a_1, a_2, \ldots, a_{n-1} are n roots of unity, then the value of (1 - a_1)(1 - a_2)(1 - a_3) \cdots (1 - a_{n-1}) is equal to
What is the digit in the unit's place of \((1008)^{786}\)?
Let \omega be the imaginary cube root of unity and (a + b\omega + c\omega^2)^{2015} = (a + b\omega^2 + c\omega) where a, b, c are unequal real numbers. Then the value of a^2 + b^2 + c^2 - ab - bc - ca equals:
If \text{Im}\left(\frac{z-1}{2z+1}\right) = -4, then locus of z is
If x^2 - x + 1 = 0, then the value of \sum_{n=1}^{5} x^n + x^{-n} is
261. Let \(z\) be the complex number satisfying \(|z + 16| = 4|z + 1|\), then:
Let four points \(z_1, z_2, z_3, z_4\) be in complex plane such that \(|z_1|
All three roots of az3 + bz2 + cz + d = 0, have negative real part, where (a, b, c ∈ ℝ). Then:
If a = \cos \alpha + i \sin \alpha, b = \cos \beta + i \sin \beta, c = \cos \gamma + i \sin \gamma and \frac{b}{c} + \frac{c}{a} + \frac{a}{b} = 1, then \cos(\beta - \gamma) + \cos(\gamma - \alpha) + \cos(\alpha - \beta) is equal to
Let z be a complex number satisfying |z - 3| ≤ |z - 1|, |z - 3| ≤ |z - 5|, |z - i| ≤ |z + i| and |z - i| ≤ |z - 5i|. Then the area of region in which z lies is A square units, where A = ?
730. Let \(z\) (\(z \in\) complex number) be one of the roots of the equation \(x^2 - (\log_2 \alpha - \log_2 \beta)x + \cos\alpha - \sin\beta = 0\). If the harmonic mean of the roots is 2 and \(|z| = 1\), find the sum of all values of \(\beta\) in degrees when \(0
The sequence S = i + 2i2 + 3i3 + 4i4 + ... up to 100 terms simplifies to, where i = \(\sqrt{-1}\)
Find the locus of a complex number z = x + iy, which satisfy the equation \(\frac{z - 5i}{z + 5i} = 1\).