If the complex number associated with the vertices \(A\), \(B\), \(C\) of \(\triangle ABC\) are \(e^{i\theta}\), \(\omega\), \(\bar{\omega}\), respectively [where \(\omega\), \(\bar{\omega}\) are the complex cube roots of unity and \(\cos\theta > \text{Re}(\omega)\)], then the complex number of the point where the angle bisector of \(A\) meets the circumcircle of the triangle is
If the equation \(z^4 + a_1 z^3 + a_2 z^2 + a_3 z + a_4 = 0\), where \(a_1, a_2, a_3, a_4\) are real coefficients different from zero, has a purely imaginary root, then the expression \(\dfrac{a_3}{(a_1 a_2)} + \dfrac{a_1 a_4}{(a_2 a_3)}\) has the value equal to
If z1, z2, z3, ..., zn are n nth roots of unity, then for k = 1, 2, 3, ..., n
Match List-I with List-II (for $z=x+iy$, $x,y\in\mathbb{R}$): P) Area of triangle formed by $z,\omega z,z+\bar{\omega}z$ is $16\sqrt{3}$ then $|z|$; Q) Area of locus of $z$ if $|\text{Re}\,z|+|\text{Im}\,z|=3$; R) If $|z+6/z|=5$ then maximum of $|z|$; S) Number of complex numbers $z$ satisfying $z^2=\bar{z}$