Let A ∈ (0, 0), B ∈ (5, 0), C ∈ (5, 3) and D ∈ (0, 3) are the vertices of rectangle ABCD. If P is a variable point lying inside the rectangle ABCD and d(P, L) denotes perpendicular distance of point P from line L. If d(P, AB) ≤ min{d(P, BC), d(P, CD), d(P, AD)}, then area of the region in which P lies is :
Consider three curves $H:(x+a)y=\lambda$, $\lambda<0$, $a>0$; $C: x^2+y^2-21y+109=0$; $P: y^2=bx$, $b>0$. Let the line $2x-y+8=0$ touch $H$, $C$ and $P$ at $L$, $M$, $N$ respectively such that $LM=MN=\sqrt{45}$. Then $8\lambda+b+a$ is
Let $S=\{(x,y)\in\mathbb{R}\times\mathbb{R}: y^2\leq8x,\;y^2\geq32-8x,\;x+y-6\geq0,\;4x-3y-8\leq0,\;x\geq0,\;y\geq0\}$. If area $=A$, value of $21A+792$ is