If \(\begin{vmatrix} a & a^2 & 1+a^3 \\ b & b^2 & 1+b^3 \\ c & c^2 & 1+c^3 \end{vmatrix} = 0\) and \((1, a, a^2)\), \((1, b, b^2)\), \((1, c, c^2)\) are non-coplanar, then \(abc\) equals:
If \(a, b, c\) are in G.P. with common ratio \(r_1\) and \(\alpha, \beta, \gamma\) are in G.P. with common ratio \(r_2\), and equations \(ax + \alpha y + z = 0\), \(bx + \beta y + z = 0\), \(cx + \gamma y + z = 0\) have only zero solution, then which of the following is not true?
If a, b and c are sides of \(\triangle ABC\) such that\[a^3 + b^3\cos B + c^3\cos A + b^2 + c^2 = 0\]\[c^3 + a^3\cos B + a^2\cos A + c^2 + a^2 = 0\]\[b^3 + a^3\cos B + b^3\cos A + a^2 + b^2 = 0\]where \(\phi, \psi, \omega \in \mathbb{R}\) and \(\angle A, \angle B, \angle C \in [\frac{\pi}{8}, \frac{7\pi}{8}]\), then \(\triangle ABC\) is