Determinants Questions (2072)

If \(\det(A)\)=5, then det(A\)^6(I\) + \(A\)⁻^6)(I\) - \(A\)⁻^6)) equals:
If \(\det(A)\)=k, then det(A\)^n(I\) - \(A\)⁻^n)(I\) + \(A\)⁻^n)(I\) - \(A\)⁻^n)(I\) + \(A\)⁻^n)) equals:
Value of \(\begin{vmatrix} x+y & z & z \\ x & y+z & x \\ y & y & z+x \end{vmatrix}\), where \(x, y, z\) are nonzero real numbers, is equal to
If \(\det(A)\)=3, then det(A\)^4(A\)⁻^4 + \(I)(A\)⁻^4 - \(I)(A\)⁻^4 + \(I)) equals:
If \(\Delta(x) = \begin{vmatrix} \tan x & \tan(x+h) & \tan(x+2h) \\ \tan(x+2h) & \tan x & \tan(x+h) \\ \tan(x+h) & \tan(x+2h) & \tan x \end{vmatrix}\), then the value of \(\lim_{h \to 0} \dfrac{\Delta(\pi/3)}{\sqrt{3}h^2}\) is
If \(\det(A)\)=k, then det(A\)^n(A\)⁻^n + \(I)(A\)⁻^n - \(I)(A\)⁻^n + \(I)) equals:
If \(\det(A)\)=k, then det(A\)^n(I\) + \(A\)⁻^n)(I\) - \(A\)⁻^n)) equals:
For Problems 14 and 15\(A\) and \(B\) are square matrices such that det.\((A) = 1\), \(BB^T = I\), det.\((B) > 0\), and \(A(\text{adj.}A + \text{adj.}B) = B\).The value of det.\((A + B)\) is
If \(\det(A)\)=3, then det(A\)^4(I\) + \(A\)⁻^4)(I\) - \(A\)⁻^4)) equals:
If A, B, C are nonsingular square matrices of order 3 × 3 then which of the following is not necessarily true?
If \(\det(A)\)=5, then det(A\)^6(A\)⁻^6 + \(I)(A\)⁻^6 - \(I)(A\)⁻^6 + \(I)) equals:
The system of linear equations\(x + y + z = 5\)\(x + 2y + 2z = 6\)\(x + 3y + \lambda z = \mu\)has infinitely many solutions. Find \(\lambda + \mu\).
If determinant is zero, matrix is:
If \(A\) is an idempotent matrix satisfying \((I - 0.4A)^{-1} = I - \alpha A\), where \(I\) is unit matrix of the same order as that of \(A\), then the value of \(\alpha\) is:
Choose the correct answer
Let \(A = \begin{pmatrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \end{pmatrix}(10)\) and \(B = \begin{pmatrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \end{pmatrix}\). If \(B\) is the inverse of matrix \(A\), then \(\alpha\) is
How many different diagonal matrices of order n can be formed which are involuntary?
If \[\begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} \cdot \begin{bmatrix} 1 & 2 \\ 0 & 1 \end{bmatrix} \cdot \begin{bmatrix} 1 & 3 \\ 0 & 1 \end{bmatrix} \cdots \begin{bmatrix} 1 & n-1 \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 78 \\ 0 & 1 \end{bmatrix},\] then the inverse of \(\begin{bmatrix} 1 & n \\ 0 & 1 \end{bmatrix}\) is:
If nth-order square matrix A is an orthogonal, then \(|\text{adj}(\text{adj } A)|\) is
If \(B\) is a \(3 \times 3\) matrix such that \(B^2 = 0\), then \(\det[(I+B)^{50} - 50B]\) is equal to
If determinant is triangular, then off-diagonal elements:
If \(A\) is an invertible matrix, then \((\text{adj } A)^{-1}\) is equal to
For Problems 22–24Consider the system of equations\(x + y + z = 6\)\(x + 2y + 3z = 10\)\(x + 2y + \lambda z = \mu\)The system has no solution if
If \(A = \begin{bmatrix} 1 & \tan x \\ -\tan x & 1 \end{bmatrix}\), then \(A^T A^{-1}\) is
If \(\Delta\) = \[ \begin{vmatrix} a & b & c \\ d & e & f \\ g & h & i \end{vmatrix} \] and one row is replaced by sum of two rows, determinant becomes:
If \(\det(A)\)=5, then det(A\)^5A^3A⁻^7A^{-1}) equals:
If determinant has identical columns, then determinant equals:
Let \(A = \begin{pmatrix} \cos\alpha & -\sin\alpha \\ \sin\alpha & \cos\alpha \end{pmatrix}\), \((\alpha \in \mathbb{R})\) such that \(A^{32} = \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}\). Then a value of \(\alpha\) is:
Which of the following is an orthogonal matrix?
If the following system of equations is consistent,\((a+1)^3x + (a+2)^3y = (a+3)^3\)\((a+1)x + (a+2)y = a+3\)\(x + y = 1\),then find the value of \(a\).
If det(A)=3, then det(2\(A\)^{-1}) for 3 \times 3 matrix equals:
If \(\alpha, \beta, \gamma\) are the roots of \(ax^3 + bx^2 + cx + d = 0\) and \[\begin{vmatrix} \alpha & \beta & \gamma \\ \beta & \gamma & \alpha \\ \gamma & \alpha & \beta \end{vmatrix} = 0,\] \(\alpha \neq \beta \neq \gamma\), then find the equation whose roots are \(\alpha+\beta-\gamma\), \(\beta+\gamma-\alpha\), and \(\gamma+\alpha-\beta\).
Let \(A = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 0 & 5 \\ 0 & 2 & 1 \end{bmatrix}\) and \(B = \begin{bmatrix} 0 \\ -3 \\ 1 \end{bmatrix}\). Which of the following is true?
If \( P = \begin{bmatrix} \dfrac{\sqrt{3}}{2} & \dfrac{1}{2} \\ -\dfrac{1}{2} & \dfrac{\sqrt{3}}{2} \end{bmatrix} \), \( A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} \) and \( Q = PAP^T \) and \( X = P^T Q^{2005} P \), then \( X \) is equal to
There are two numbers x making the \[ \begin{vmatrix} 1 & -2 & 5 \\ & 2 & x & -1 \\ & 0 & 4 & 2x \end{vmatrix} \] equal to 86. The sum of these numbers is:
If determinant has one column entirely zero, then its value is:
If the system of linear equations,\(x + ky + 3z = 0\)\(3x + ky - 2z = 0\)\(2x + 4y - 3z = 0\)has a non-zero solution \((x, y, z)\), then \(\dfrac{xz}{y^2}\) is equal to
If A = $$\begin{bmatrix} 3 & 4 \\ 5 & 7 \end{bmatrix}$$, then A × (adj A) is equal to
The value of the determinant \(\begin{vmatrix} ^nC_{r-1} & ^nC_r & (r+1)^{n+2}C_{r+1} \\ ^nC_r & ^nC_{r+1} & (r+2)^{n+2}C_{r+2} \\ ^nC_{r+1} & ^nC_{r+2} & (r+3)^{n+2}C_{r+3} \end{vmatrix}\) is
If \(\det(A)\)=4, then det(A\)^6A⁻^4A^{-1}) equals:
Let \(A = \begin{bmatrix} 0 & \alpha \\ 0 & 0 \end{bmatrix}\) and \((A+I)^{50} - 50A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}\). Then the value of \(a + b + c + d\) is
If \(\det(A)\)=2, then det(A\)^4A⁻^2A^{-1}) equals:
If A = \(\begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & -2 \\ a & 2 & b \end{bmatrix}\) is a matrix satisfying the equation \(AA^T = 9I\), where I is \(3 \times 3\) identity matrix, then the ordered pair \((a, b)\) is equal to
Consider a matrix \(A = [a_{ij}]\) of order \(3 \times 3\) such that \(a_{ij} = (k)^{i+j}\) where \(k \in I\).Match List I with List II and select the correct answer using the codes given below the lists.List Ia. \(A\) is singular ifb. \(A\) is null matrix ifc. \(A\) is skew-symmetric which is not null matrix ifd. \(A^2 = 3A\) ifList IIp. \(k \in \{0\}\)q. \(k \in \phi\)r. \(k \in I\)s. \(k \in \{-1, 0, 1\}\)Codes:(1) a-r, b-p, c-s, d-q(2) a-s, b-p, c-q, d-r(3) a-r, b-p, c-q, d-s(4) a-q, b-p, c-r, d-s
If \(\alpha\) and \(\beta\) are the roots of \(x^2 + x + 1 = 0\), then the value of the determinant\[\begin{vmatrix} y+1 & \beta & \alpha \\ \beta & y+\alpha & 1 \\ \alpha & 1 & y+\beta \end{vmatrix}\]is equal to
Let α be a root of the equation x2 + x + 1 = 0 and the matrix A = 1/√3 [[1, 1, 1], [1, α, α2], [1, α2, α4]], then the matrix A31 is equal to:
If \(A = \begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & -2 \\ a & 2 & b \end{bmatrix}\) is a matrix satisfying the equation \(AA^T = 9I\), where \(I\) is \(3 \times 3\) identity matrix, then the ordered pair \((a, b)\) is equal to
We have \(p = \begin{bmatrix} 1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4 \end{bmatrix}\). If \(|\text{adj}\, A| = |A|^2 \Rightarrow |\text{adj}\, A| = 16\), find \(\alpha\).
If \( P = \begin{bmatrix} \dfrac{\sqrt{3}}{2} & \dfrac{1}{2} \\ -\dfrac{1}{2} & \dfrac{\sqrt{3}}{2} \end{bmatrix} \), \( A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} \) and \( Q = PAP^T \), then \( P^T Q^{2015} P \) is
We have \[BC = \begin{bmatrix}3 & 4\\2 & 3\end{bmatrix}\begin{bmatrix}3 & -4\\-2 & 3\end{bmatrix} = I.\] Find \[\text{tr}(A) + \text{tr}\!\left(\frac{A(BC)}{2}\right) + \text{tr}\!\left(\frac{A(BC)^2}{4}\right) + \text{tr}\!\left(\frac{A(BC)^3}{8}\right) + \cdots\infty,\] given that \(A = \begin{bmatrix}2 & 1\\1 & 1\end{bmatrix}\) (so that \(\text{tr}(A)=3\) and the series converges).