Let \(\{D_1, D_2, D_3, \ldots, D_n\}\) be the set of third-order determinants that can be made with the distinct non-zero real numbers \(a_1, a_2, \ldots, a_9\). Then
If \[\begin{vmatrix} a & a^2 & 1 + a^3 \\ b & b^2 & 1 + b^3 \\ c & c^2 & 1 + c^3 \end{vmatrix} = 0\] and vectors \((1, a, a^2)\), \((1, b, b^2)\) and \((1, c, c^2)\) are non-coplanar, then the product \(abc\) equals:
17. Let \(M_n = (a_{ij})\) where \(i, j = 1, 2, 3, \ldots, n\). We first find out \(a_{11}\) for the \(n^{\text{th}}\) matrix, which is the \(n^{\text{th}}\) term in the series: \(1, 2, 6, 15, \ldots\). The diagonal elements of the \(n^{\text{th}}\) matrix form an arithmetic progression with first term \(1 + \dfrac{n(n-1)(2n-1)}{6}\) and common difference \(n+1\). Find the required sum \(M_n\).