Limits, Continuity & Differentiability Questions (1044)

Given \( x = 3\tan t,\ y = 3\sec t \), find \(\left(\dfrac{d^2 y}{dx^2}\right)_{t=\pi/4}\).
If \(\displaystyle\lim_{\alpha \to 0} \frac{e^{\cos(\alpha^n)} - e}{\alpha^m} = \frac{-e}{2}\) where \(m\) and \(n\) are positive integers greater than 1, then the value of \(\dfrac{m}{n}\) is:
\(\lim_{x \to \frac{\pi}{2}} \dfrac{\cot x - \cos x}{(\pi - 2x)^3}\) equals
The value of \(\displaystyle\lim_{x \to 0}\left\lfloor (1-e^x)\frac{\sin x}{|x|}\right\rfloor\) equals: [Note: \([\,\cdot\,]\) denotes the greatest integer function.]
\(f(x) = x^2 + 3, x \leq 1\)\(= 3x + a, x > 1\)Is \(f(x)\) neither continuous nor differentiable at \(x = 1\)?
Let \(x^3 - 2x^2y^2 + 5x + y - 5 = 0\) and at \(x = 1\), \(y = 1\). Then \(\dfrac{dy}{dx}\) at \(y = 1\) is
If \( x\log_e(\log_e x) - x^2 + y^2 = 4 \) \((y > 0)\), then \( \dfrac{dy}{dx} \) at \( x = e \) is equal to:
\(\lim_{x \to 2} [x]\) exists where \([x]\) denotes the integral part of \(x\).State whether the statement is true or false.
If \(f(x)\) is odd linear polynomial with \(f(1) = 1\), then \[\lim_{x \to 0} \frac{2^{f(\tan x)} - 2^{f(\sin x)}}{x^2 f(\sin x)}\] is
\[\lim_{n \to \infty} \frac{e^n}{\left(1 + \dfrac{1}{n}\right)^{n^2}}\] equals
If \(f(x)\) is a polynomial of least degree such that \(\lim_{x \to 0}\left(1 + \dfrac{f(x) + x^2}{x^2}\right)^{1/x} = e^2\), then \(f(2)\) is
\(\lim_{x \to 0} \dfrac{e^{x^2} - \cos x}{\sin^2 x}\) is equal to
Let \(f(x) = \begin{cases} \sqrt{x^2 - 1}, & x \leq \sqrt{10} \\ (\sqrt{10}x - 7), & \sqrt{10}
Let \(f(2) = 4\) and \(f'(2) = 4\). Then \(\displaystyle\lim_{x \to 2} \frac{xf(2) - 2f(x)}{x - 2}\) is given by
If \(f(x)\) is a real valued bijective function satisfying \(f'(x) = \sin^2(\sin(x+1))\) and \(f(0) = 3\), then the value of \((f^{-1})''(3)\) is equal to:
Let \(f: R \to R\) be a function such that \(|f(x)| \leq x^2\), for all \(x \in R\). Then at \(x = 0\), \(f(x)\) is
If \( x = e^{y + e^{y + \cdots}} \), \( x > 0 \), then \( \dfrac{dy}{dx} \) is:
Given \(f(t) = (|\lambda|e^{|t|} - \mu)\sin(2|t|)\). If \(f(t)\) is differentiable at \(t = 0\), then the set \(S\) of all possible values of \((\lambda, \mu)\) is a subset of:
The value of \(\displaystyle\lim_{x \to \infty} \frac{e^x\left[\left(2^{x^n}\right)^{1/e^x} - \left(e^{x^n}\right)^{1/e^x}\right]}{x^n}\) where \(n\) is positive integer, is:
Given \(f(x) = (x-1)^{\frac{1}{2-x}},\; x > 1,\; x \neq 2\) and \(f(2) = k\). If \(f\) is continuous at \(x = 2\), find \(k\).
If \(\lim f(x)\) and \(\lim g(x)\) exist then \(\lim [f(x) \cdot g(x)]\) exist.
Let \( f(x) = \begin{cases} (x-1)\sin\left(\dfrac{1}{x-1}\right), & \text{if } x \neq 1 \\ 0, & \text{if } x = 1 \end{cases} \). Then which one of the following is true?
If \(\sin y = x\sin(a+y)\), then \(\dfrac{dy}{dx}\) equals:
Let \(x_0 = \tan^{-1}(2)\) and \[b = \lim_{x \to \tan^{-1}2} \frac{(\tan^2 x - a)(1 + \tan x)}{e^{(\tan x - 2)} - 1}\] For the existence of the limit, find \([a + b + x_0]\) where \([\cdot]\) denotes the greatest integer function.
It is given that \(2x = y^{1/5} + y^{-1/5}\)If \(y = (x + \sqrt{x^2 - 1})^5\), then \((x^2 - 1)\dfrac{d^2y}{dx^2} + \lambda x \dfrac{dy}{dx} - 25y = 0\). Find \(\lambda + k\) where \(k = -25\).
The value of \(\lim_{x \to 0^+} x^m (\log x)^n\), \(m, n \in \mathbb{N}\) is
Given $f(x) = \begin{cases} x^2e^{-x} & 0 \leq x \leq 1 \\ a \sin(x+1) \cos(2x-2) + bx^3 & 1 < x \leq 2 \end{cases}$. If $f(x)$ is differentiable at $x = 1$, then the value of $|a - b|$ is
The value of \(\lim_{x \to 0}(f(x) + g(x) + 3)^{1/x}\) equal to:
Let \(f(x) = \left(\dfrac{4}{5}\right)^{\frac{\tan 4x}{\tan 5x}}\). If \(\displaystyle\lim_{x \to \pi/2} f(x) = k + \dfrac{2}{5}\), find the value of \(k\).
If $f(x) = \cos x\cdot\cos 2x\cdot\cos 4x\cdot\cos 8x\cdot\cos 16x$, then $f'\!\left(\dfrac{\pi}{4}\right)$ equals:
Let f(x) = x|x|, g(x) = sin x and h(x) = (g ∘ f)(x). Then
If \(\lim_{x \to 0} f(x)\) and \(\lim_{x \to 0} g(x)\) exist then \(\lim_{x \to 0} g(x)\) exist. \(\lim_{x \to 0} g(x)\) exist.
Let $f(x) = \sin\!\left(\sin^{-1}(2x)+2\tan^{-1}(2x)\right)$. If $3f'(0)=$ (integer), find it.
Let \(f(x)=x\), \(g(x)=|1-f(x)|\), \(h(x)=2-g(x)\), \(L(x)=h(|x|)+|h(x)|\). Find the number of points where \(L(x)\) is non-differentiable.
If \( y = \sec(\tan^{-1} x) \), then \( \dfrac{dy}{dx} \) at \( x = 1 \) is equal to:
If \(x\log_e(\log_e x) - x^2 + y^2 = 4\), then \(\dfrac{dy}{dx}\) at \(x = e\) is equal to:
If \(f(x)\) is a differentiable function in the interval \((0, \infty)\) such that \(f(1) = 1\) and \(\lim_{t \to x} \dfrac{t^2 f(x) - x^2 f(t)}{t - x} = 1\), for each \(x > 0\), then \(f(3/2)\) is equal to
State whether the statement is true or false: \(\lim_{y \to 0} \frac{\log(1+x)}{3^y - 1} = \frac{1}{\log_e 3}\)
Let \(f\) and \(g\) be inverse functions of each other. If \(f(1) = 3\) and \(f'(1) = 4\), then \(g'(3)\) equals:
If \(\lim_{x \to 0} \frac{1-\cos 2x \sin 5x}{x^2 \sin 3x} = \frac{10}{3}\)State whether this statement is true or false.
\(\lim_{x \to 0} \dfrac{(2x)^4\left(\dfrac{1-\cos 2x}{4x^2}\right)^2}{2x\left(\tan x - \dfrac{\tan 2x}{2}\right)}\)
Consider the function \( f(x) = |x-2| + |x-5|, \, x \in R \).Statement-1: \( f'(4) = 0 \).Statement-2: \( f \) is continuous in \([2, 5]\), differentiable in \((2, 5)\) and \( f(2) = f(5) \).
If \(f(x) = \tan^2\left[x - \frac{\pi}{4}\right]\) where \([x]\) is the greatest integer function then:
If \(|f(x)| \leq x^2\), then which of the following is true?
Let \( f: R \to R \) be a function defined by \( f(x) = \min\{x+1,\ |x|+1\} \). Then which of the following is true?
If $f(x) = \begin{cases} x\tan^{-1}x\cdot\sec^{-1}\!\left(\dfrac{1}{x}\right), & x\in(-1,1)\setminus\{0\} \\ \dfrac{\pi}{2}, & x=0 \end{cases}$, then $f'(0)$ is:
\(\lim_{x \to 4} \frac{\cos x - \cos a}{\cos x - \cot a} = \sin^3 a\)State whether this is true or false.
Evaluate: \[\lim_{x \to 3} \frac{\sqrt{3x} - 3}{\sqrt{2x - 4} - \sqrt{2}}\]
If \(f(c) = 2\), \(f'(c) = 1\), \(g(c) = -1\), \(g'(c) = 2\) then \(\lim_{x \to c} \frac{g(x)f(c) - g(c)f(x)}{x - c} =\) ______
The derivative of \(\tan^{-1}\left(\dfrac{\sin x - \cos x}{\sin x + \cos x}\right)\), with respect to \(\dfrac{x}{2}\), where \(x \in \left(0, \dfrac{\pi}{2}\right)\) is: