Consider the following statementsStatement-1 : If A is an idempotent non-zero matrix and I is an identity matrix of the same order, such that (A + I)n = I + 127 A. (n ∈ N), then 'n' has 3 positive divisors.Statement-2 : Let A = 3x216x, B = [a b c] and C = (x+2)25x22x5x22x(x+2)22x(x+2)25x2 be three given matrices, where a, b, c and x ∈ R. Given that tr(AB) = tr(C) ∀ x ∈ R, where tr(A) denotes trace of A. Solving, we get a + b + c = 7.Then, which of the following options is/are correct ?
Let α be a root of the equation x2 + x + 1 = 0 and the matrix A = 1/√3 [[1, 1, 1], [1, α, α2], [1, α2, α4]], then the matrix A31 is equal to:
22. $D = \begin{vmatrix} 10^4 + 2 & 10^7 + 3 & 10^8 + 8 \\ 10^9 + 9 & 10^2 + 8 & 10^3 - 4 \\ 10^3 - 5 & 10^8 + b & 10^6 + a \end{vmatrix}$ where $a, b$, both $\in \{1,2,3,4,5,6,7,8,9\}$Number of ordered pairs $(a, b)$ such that $D = 2n + 1, n \in Z$ is
Let M = \begin{pmatrix} \sin^2 \theta & -1-\sin^2 \theta \\ 1+\cos^2 \theta & \cos^2 \theta \end{pmatrix} = \alpha I + \beta M^{-1}, where \alpha = \alpha(\theta) and \beta = \beta(\theta) are real number, and I is the 2 \times 2 identity matrix. If \alpha^* is the minimum of the set \{\alpha(\theta): \theta \in [0, 2\pi]\} and \beta^* is the minimum of the set \{\beta(\theta): \theta \in [0, 2\pi]\}, then the value of \alpha^* + \beta^* is