One function is selected from all the functions \(F : S \to S\), where \(S = \{1, 2, 3, 4, 5, 6\}\). The probability that it is onto function, is
We have \(A = \{4, 5, 6\}\), \(B = \{1, 2, 3, 4\}\). We have \(A \cup B = \{1, 2, 3, 4, 5, 6\} = S\) where \(S\) is the sample space of the experiment of throwing a die, so \(P(S) = 1\). Hence \(P(A \cup B) =\)?
For independent events \(A_1, A_2, \ldots, A_n\), \(P(A_i) = \frac{1}{i+1}\), \(i = 1, 2, \ldots, n\). Then, the probability that none of the events will occur is