Home
/
Directory
/
JEE
/ Quadratic Equations
Quadratic Equations Questions (527)
If no value of $\theta$
Find the number of positive integers satisfying the inequality \(x^2 - 10x + 16
If the equation \((1+m)x^2 - 2(1+3m)x + (1+8m) = 0\), where \(m \in \mathbb{R} \setminus \{-1\}\), has at least one root is negative, then
23. Suppose that \(x_1\) and \(x_2\) are the positive real solution of \(x^2 - bx + c = 0\) provided that \(x_1^2 + \sqrt{x_2^2 - 2x_2} = 2x_1 - 1\). The minimum value of \((b + c)\), is:
Let $\alpha,\beta$ be the roots of the equation $x^2+2\sqrt{2}x-1=0$. The quadratic equation, whose roots are $\alpha^4+\beta^4$ and $\dfrac{1}{10}(\alpha^6+\beta^6)$, is:
Given that the quadratic equation \(x^2 - 64x + 256 = 0\) has roots \(a\) and \(b\), find the value of \(\left(\frac{a^3}{b^5}\right)^{1/8} + \left(\frac{b^3}{a^5}\right)^{1/8}\).
If $\sin\theta = \frac{7\sin\theta}{11\cos\theta}$
Let \(\sum_{r=1}^{10}(r+r \times \binom{10}{r}) = 2^{10}(a \times 4^5 + b)\) where \(a, b \in \mathbb{N}\) and \(f(x) = x^2 - 2x - k^2 + 1\).If a and b lie between the roots of \(f(x) = 0\), then find the smallest positive integral value of k.
For $x\in\mathbb{R}$, the expression $\dfrac{x^2+2x+c}{x^2+4x+3c}$ can take all real values if $c\in$
The sum of the squares of the roots of $|x + 2| + |x - 2| - 2 = 0$ and the squares of the roots of $2x^2 - 2|x - 3| - 5 = 0$ is
77. All the values of \(m\) for which both the roots of the equation \(x^2 - 2mx + m^2 - 1 = 0\) are greater than \(-2\) but less than 4 lie in the interval
76. If roots of \(x^2 - (a-3)x + a = 0\) are such that at least one of them is greater than 2, then
The number of real solutions of \(|x - 2\sqrt{5 - 4x - x^2}| = 16\) is/are
The sum of values of x satisfying the equation \((31 + 8\sqrt{15})^{x^2 - 3} + 1 = (32 + 8\sqrt{15})^{x^2 - 3}\) is
tan α and tan β are the roots of the equation \(x^2 + ax + b = 0\), then the value of \(\sin^2(α + β) + a\sin(α + β)\cos(α + β) + b\cos^2(α + β)\) is equal to
Two students while solving a quadratic equation in x, one copied the constant term incorrectly and got the roots 3 and 2. The other copied the coefficient of x² correctly as -6 and 1 respectively the correct roots are
Solve \(\sqrt{x-2}\,(x^2-4x-5)=0\).
Ex. 62: If the sum of the base 2 logarithms of the roots of the cubic \(f(x) = 0\) is 5, then the value of \(a\) is
If \(x^4 + 3x^3 + 2(1-a)x^2 - 3ax + a^2 = 0\) has only real roots then which of the following may be the value of \(a\)?
The given equation is \(-3(x - [x])^2 + 2(x - [x]) + a^2 = 0\). The values of \(a\) for which the equation has non-integral solutions satisfy:
If roots of the equation \(\dfrac{1}{x-a} + \dfrac{1}{x-b} + \dfrac{1}{x-c} + \dfrac{1}{x-d} + \dfrac{(x-2)(x^2+2x+4)}{(x-a)(x-b)(x-c)(x-d)} = 0\) are \(\alpha\), \(\beta\) and \(\gamma\), then sum of the roots of the equation \(5(x-\alpha)(x-\beta)(x-\gamma) + 8 - x^3 = 0\) is:
Given equation is \(bx^3 + cx + a = 0\). The roots are imaginary if \(c^2 - 4ab
If \(x^4 + 3x^3 + 2(1-a)x^2 - 3ax + a^2 = 0\) has only real roots then which of the following may be the value of \(a\)?
The range of value of \(\lambda\) for which the expression \(\dfrac{2x^2 - 5x + 3}{4x - \lambda}\) can take all real values for \(x \in R - \left\{\dfrac{\lambda}{4}\right\}\), is:
If the expression \([mx - 1 + (1/x)]\) is non-negative for all positive real \(x\), then the minimum value of \(m\) must be
Let a > 2 be a constant. If there are just 18 positive integers satisfying the inequality \((x - a)(x - 2a)(x - a^2) < 0\), then find the value of a.
If the equation \(ax^2 + bx + c = 0\), where \(a, b, c \in \mathbb{R}\) and \(a > 0\), has two real roots \(\alpha\) and \(\beta\) such that \(\alpha and \(\beta > 2\), then
← Previous Page
Next Page →