138. Let a polynomial \(P(x)\), when divided by \(x-1\), \(x-2\), \(x-3\) leaves the remainder 4, 5, 6 respectively. When \(P(x)\) is divided by \((x-1)(x-2)(x-3)\), the remainder is \(ax^2+bx+c\), then \(3a+2b+c\) is equal to:
If the set of all $a\in\mathbb{R}$, for which the equation $2x^{2}+(a-5)x+15=3a$ has no real root, is the interval $(\alpha,\beta)$, and $X=\{x\in\mathbb{Z}\,:\,\alpha<x<\beta\}$, then $\displaystyle\sum_{x\in X}x^{2}$ is equal to:
138. Let a polynomial \(P(x)\), when divided by \(x-1,\, x-2,\, x-3\) leaves the remainder \(4,\,5,\,6\) respectively. When \(P(x)\) is divided by \((x-1)(x-2)(x-3)\), the remainder is \(ax^2+bx+c\), then \(3a+2b+c\) is equal to: