For Problems 13–15: Consider the sequence in the form of groups \((1), (2, 2), (3, 3, 3), (4, 4, 4, 4), (5, 5, 5, 5, 5), \ldots\)The sum of first 2000 terms is
If \(a_1, a_2, a_3 \ldots a_n\) are in H.P. and \(f(k) = \left(\sum_{r=1}^{n} a_r\right) - a_k\), then \(\dfrac{a_1}{f(1)}, \dfrac{a_2}{f(2)}, \dfrac{a_3}{f(3)}, \ldots, \dfrac{a_n}{f(n)}\) are in
If \(x, a\) and \(b\) are in A.P., \(a, y\) and \(b\) are in G.P., and \(a, z, b\) are in H.P. such that \(x = 9z\) and \(a > 0, b > 0\), then
If \(a_1, a_2, a_3, \ldots\) are in A.P., then \(a_p, a_q, a_r\) are in A.P. if \(p\), \(q\), \(r\) are in
How many triplets (a, b, c) exist such that a, b, c, b + c – a, c + a – b, a + b – c, and a + b + c form 7 term arithmetic progression in some order. Here (a, b, c) are distinct positive real numbers.
If \(a, b\) and \(c\) are in A.P., \(p, q\) and \(r\) are in H.P., and \(ap, bq, cr\) are in G.P., then \(\dfrac{p}{r} + \dfrac{r}{p}\) is equal to