Vertices of a parallelogram \(ABCD\) are \(A(3, 1)\), \(B(13, 6)\), \(C(13, 21)\) and \(D(3, 16)\). If a line passing through the origin divides the parallelogram into two congruent parts then the slope of the line is:
An altitude BD and a bisector BE are drawn in the triangle ABC from the vertex B. It is known that the length of side AC = 1, and the magnitudes of the angles \(\angle BEC\), \(\angle ABD\), \(\angle ABE\), \(\angle BAC\) form an arithmetic progression.Let B' be the image of point B with respect to side AC of \(\triangle ABC\), then the length BB' is equal to:
Let \(A = (0, 0)\), \(B = (5, 0)\), \(C = (5, 3)\) and \(D = (0, 3)\) are the vertices of rectangle ABCD. If P is a variable point lying inside the rectangle ABCD and \(d(P, L)\) denote perpendicular distance of point P from line L. If \(d(P, AB) \leq \min\{d(P, BC), d(P, CD), d(P, AD)\}\), then area of the region in which P lies is:
A(6, 3), B(-3, 5), C(4, -2) and D(x, 3x) are four points. If the area of \triangle DBC and \triangle ABC are in the ratio 1:2, then x is equal to
Let the area of a $\triangle PQR$ with vertices $P(5,4)$, $Q(-2,4)$ and $R(a,b)$ be $35$ square units. If its orthocenter and centroid are $O\!\left(2,\dfrac{14}{5}\right)$ and $C(c,d)$ respectively, then $c+2d$ is equal to
Let the triangle $PQR$ be the image of the triangle with vertices $(1,3)$, $(3,1)$ and $(2,4)$ in the line $x+2y = 2$. If the centroid of $\triangle PQR$ is the point $(\alpha,\beta)$, then $15(\alpha-\beta)$ is equal to:
Let $A(-2,-1)$, $B(1,0)$, $C(\alpha,\beta)$ and $D(\gamma,\delta)$ be the vertices of a parallelogram $ABCD$. If the point $C$ lies on $2x-y=5$ and the point $D$ lies on $3x-2y=6$, then the value of $|\alpha+\beta+\gamma+\delta|$ is equal to
If $(\alpha,\beta)$ is the orthocentre of $\triangle ABC$ with $A(3,-7)$, $B(-1,2)$, $C(4,5)$, then $9\alpha-6\beta+60$ is equal to
Let A(6, 8), B(10 cos \alpha, -10 sin \alpha) and C(-10 sin \alpha, 10 cos \alpha), be the vertices of a triangle. If L(a, 9) and G(h, k) be its orthocenter and centroid respectively, then (5a - 3h + 6k + 100 sin 2\alpha) is equal to ______ -.
Line $\frac{x}{a} + \frac{y}{b} = 1$ cuts the coordinate axes at $A(a, 0)$ and $B(0, b)$ and the line $\frac{x}{a'} + \frac{y}{b'} = -1$ at $A'(-a', 0)$ and $B'(0, -b')$. If the points $A$, $B$, $A'$, $B'$ are concyclic then the orthocentre of the triangle $ABA'$ is: