Determinants Question - CBSE

Question

Area of a triangle with vertices $(3, 8), (-4, 2)$ and $(5, 1)$ is:
(a) $\dfrac{61}{2}$ sq. units
(b) $\dfrac{31}{2}$ sq. units
(c) $61$ sq. units
(d) $\dfrac{45}{2}$ sq. units

Accepted Answer

$ ext{Area} = \dfrac{1}{2} |3(1) - 8(-9) + 1(-14)| = \dfrac{1}{2} |3 + 72 - 14| = \dfrac{61}{2}$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Evaluating area $= 61/2$ sq. units: 1.0 Mark

Question:

Step-by-Step Solution

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