Application of Derivatives
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
The maximum slope of the curve $y = -x^3 + 3x^2 + 9x - 27$ is:
(a) $12$
(b) $9$
(c) $15$
(d) $0$
Step-by-Step Solution
Slope S = dy/dx = -3x^2 + 6x + 9. Max S occurs at x = 1 where S = 12. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting $12$: 1.0 Mark
Correct Answer: $12$
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