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Quadratic Equations

RD Sharma

CBSE

Grade 10

Question:

Find the nature of the roots of $2x^2 - 6x + 3 = 0$.

Step-by-Step Solution

Key Concept: $D = 36 - 24 = 12 > 0 \Rightarrow$ Real and distinct roots.

$D = (-6)^2 - 4(2)(3) = 36 - 24 = 12$. [1.0 Mark]
Since $D > 0$, the roots are real and distinct (unequal). [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Calculating $D = 12$: 1.0 Mark
Stating nature of roots: 1.0 Mark

Correct Answer:

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