Inverse Trigonometric Functions
Xam Idea
CBSE
Grade 12
Question:
Find the principal value of $\sec^{-1}(-\sqrt{2})$.
Step-by-Step Solution
Key Concept: sec^{-1}(-\sqrt{2}) = \pi - sec^{-1}(\sqrt{2}) = \pi - \pi/4 = 3\pi/4.
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Correct Answer:
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