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Algebra
Quadratic Equations, Symmetric Functions
jee_main_2026_april_8_shift_2
Grade None

Question:

If α and β are the roots of x² - 6x + 4 = 0, find the value of α² + β².
A. 20
B. 24
C. 28
D. 32

Step-by-Step Solution

Key Concept: α² + β² = (α+β)² - 2αβ.
Step 1: α+β = 6, αβ = 4. Step 2: α² + β² = (α+β)² - 2αβ = 36 - 8 = 28.
Correct Answer: C
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