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Some Applications of Trigonometry
CH09 Question Bank
CBSE_CH09_QUESTION_BANK
Grade 10
Question:
A tower is $30$ m high. If the angle of elevation of its top from a point on the ground is $60^\circ$, the distance of the point from the base of the tower is:
$10$ m
$10\sqrt3$ m
$30$ m
$30\sqrt3$ m
$10$ m
$10\sqrt3$ m
$30$ m
$30\sqrt3$ m
Step-by-Step Solution
Key Concept: Apply tanθ = height/distance and solve for distance.
$\tan60^\circ=\dfrac{30}{d}\Rightarrow \sqrt3=\dfrac{30}{d}$. [0.5 Mark]
$d=\dfrac{30}{\sqrt3}=10\sqrt3$ m. [0.5 Mark]
$d=\dfrac{30}{\sqrt3}=10\sqrt3$ m. [0.5 Mark]
Correct Answer: $10\sqrt3$ m
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