Integrals
NCERT Class 12
CBSE
Grade 12
Question:
The value of $\int_0^1 \dfrac{dx}{1 + x^2}$ is:
(a) $\dfrac{\pi}{4}$
(b) $\dfrac{\pi}{2}$
(c) $\pi$
(d) $0$
Step-by-Step Solution
$[\tan^{-1} x]_0^1 = \pi/4 - 0 = \pi/4$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Evaluating definite integral $= \pi/4$: 1.0 Mark
Correct Answer: $\dfrac{\pi}{4}$
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