3D Geometry
Shortest Distance between Lines
Grade 12
Question:
<p>The shortest distance between the lines \(\frac{x - 3}{7} = \frac{y - 8}{-6} = \frac{z - 3}{1}\) and \(\frac{x + 3}{1} = \frac{y + 7}{-2} = \frac{z - 6}{1}\) is</p>
<p>(a) \(3\sqrt{30}\)</p>
<p>(b) \(2\sqrt{30}\)</p>
<p>(c) \(\frac{\sqrt{30}}{7}\)</p>
<p>(d) 3</p>
Step-by-Step Solution
Key Concept: Use the formula for shortest distance between two skew lines given in symmetric form.
Solution not provided in text. (JEE Main 2020)
Correct Answer: Not specified