Continuity and Differentiability
RS Aggarwal
CBSE
Grade 12
Question:
If $y = \sin^{-1}(x)$, then $(1 - x^2) y_2 - x y_1$ is equal to:
(a) $0$
(b) $1$
(c) $-1$
(d) $y$
Step-by-Step Solution
Key Concept: y1 = 1/\sqrt{1-x^2} => (1-x^2)y1^2 = 1 => 2(1-x^2)y1 y2 - 2x y1^2 = 0 => (1-x^2)y2 - x y1 = 0.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: $0$
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