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Application of Derivatives
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
Show that height of open cylinder of given surface area $K$ and maximum volume is equal to radius of its base.
Step-by-Step Solution
Given: Problem statement: Show that height of open cylinder of given surface area $K$ and maximum volume is equal to radius of its base. Step 1: Set up geometric relations and constraint equation: Relate variables using given perimeter/surface area constraint. [1.0 Mark] Step 2: Express objective function in single variable: Substitute constraint to get objective function $f(x)$. [1.0 Mark] Step 3: Differentiate and find critical points ($f'(x) = 0$): Compute first derivative and solve for critical variable value. [1.0 Mark] Step 4: Execute Second Derivative Test ($f''(x)$): Verify sign of second derivative to confirm maximum/minimum. [1.0 Mark] Step 5: Calculate optimal dimensions/value: Substitute critical value back to state complete dimensions. [1.0 Mark] Conclusion: Optimal dimensions derived successfully.
--- 🎯 Official CBSE Marking Scheme: Setting up constraint and objective function: 1.0 Mark Evaluating first derivative f'(x): 1.0 Mark Finding critical points: 1.0 Mark Second derivative test for max/min: 1.0 Mark Evaluating final dimensions/maximum value: 1.0 Mark
Correct Answer:
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