Step-by-Step Solution
Key Concept: Line 1: $(0,1), (4,5), (-1,0)$. Line 2: $(0,6), (4,0), (2,3)$. Intersection point $(2,3)$. x-axis intercepts $(-1,0)$ and $(4,0)$. Vertices $(-1,0), (4,0), (2,3)$. Area $= \\dfrac{1}{2} \\times 5 \\times 3 = 7.5$ sq. units.
Table of points: Line 1 passes through $(-1,0), (0,1), (2,3)$. Line 2 passes through $(4,0), (0,6), (2,3)$. [1.0 Mark]
Plotting lines on graph: Intersection point is $(2,3)$. x-axis intercepts are $A(-1,0)$ and $B(4,0)$. [1.0 Mark]
Vertices of triangle: $(-1,0), (4,0), (2,3)$. Shaded region area $= 1/2 \times 5 \times 3 = 7.5$ sq. units. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Finding points and intersection $(2,3)$: 1.0 Mark
Plotting lines correctly on graph: 1.0 Mark
Writing vertices $(-1,0), (4,0), (2,3)$ and shading region: 1.0 Mark
Correct Answer: