Continuity and Differentiability
Oswaal
CBSE
Grade 12
Question:
Find value of $k$ if $f(x) = \begin{cases} \dfrac{1 - \cos 4x}{8x^2}, & x
eq 0 \\ k, & x = 0 \end{cases}$ is continuous at $x = 0$.
Step-by-Step Solution
Key Concept: lim_{x->0} (2 sin^2 2x)/(8x^2) = 1 = k.
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Correct Answer:
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