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Linear Programming
Oswaal
CBSE
Grade 12

Question:

Corner points of feasible region for $Z = 2x + 3y$ are $(0, 2), (3, 0), (1, 1)$. Minimum value of $Z$ is:
(a) $4$
(b) $5$
(c) $6$
(d) $0$

Step-by-Step Solution

Key Concept: Z(0,2)=6, Z(3,0)=6, Z(1,1)=5
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: $4$
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