Application of Derivatives
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
The minimum value of $4 e^{2x} + 9 e^{-2x}$ is:
(a) $12$
(b) $13$
(c) $25$
(d) $6$
Step-by-Step Solution
AM >= GM: (4 e^{2x} + 9 e^{-2x})/2 >= \sqrt{36} = 6 \implies min is 12. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting $12$: 1.0 Mark
Correct Answer: $12$
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