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Application of Integrals

Oswaal

CBSE

Grade 12

Question:

Area bounded by $y = x^2 + 1, y = x, x = 0, x = 2$ is:
(a) $14/3$
(b) $10/3$
(c) $4$
(d) $8/3$

Step-by-Step Solution

Key Concept: \int_0^2 (x^2 + 1 - x) dx = [x^3/3 + x - x^2/2]_0^2 = 8/3 + 2 - 2 = 8/3 + 2 = 14/3.

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Correct Answer: $14/3$

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