The angle of elevation of a cloud from a point $250$ m above a lake is $15°$ and angle of depression of its reflection in the lake is $45°$. The height of the cloud is
Step-by-Step Solution
Key Concept: Apply angle of elevation and angle of depression concepts using tangent ratios to find distances in inclined plane problems.
Given height $h = 250$ m, elevation angle $\alpha = 15°$, and angle of depression $\theta = 45°$. Using the tangent relationship with these angles and the configuration shown, the horizontal distance and resulting calculation yield a distance of $250\sqrt{3}$ m.
Correct Answer: 250√3