Question:
Centres of the three circles <span class="math-inline">\(x^{2} + y^{2} - 4x - 6y - 14 = 0\)</span>, <span class="math-inline">\(x^{2} + y^{2} + 2x + 4y - 5 = 0\)</span> and <span class="math-inline">\(x^{2} + y^{2} - 10x - 16y + 7 = 0\)</span>
(A) are the vertices of a right triangle
(B) the vertices of an isosceles triangle which is not regular
(C) vertices of a regular triangle
(D) are collinear
Step-by-Step Solution
Key Concept: General
The area of the triangle formed by these three points is given by the formula...
Correct Answer: 2