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Application of Derivatives
RS Aggarwal
CBSE
Grade 12

Question:

Slope of tangent to curve $y = x^3 - x + 1$ at point where $x$-coordinate is $2$ is:
(a) $11$
(b) $10$
(c) $12$
(d) $8$

Step-by-Step Solution

Key Concept: dy/dx = 3x^2 - 1 = 11 at x=2.
The detailed step-by-step mathematical proof is available inside the Mathbee app workspace.
Correct Answer: $11$
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