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Application of Derivatives
Oswaal
CBSE
Grade 12

Question:

A manufacturer can sell $x$ items at price of Rs $(5 - x/100)$ each. Cost price of $x$ items is Rs $(x/5 + 500)$. Find number of items he should sell to earn maximum profit.

Step-by-Step Solution

Key Concept: Profit P(x) = x(5 - x/100) - (x/5 + 500) = 24x/5 - x^2/100 - 500. P'(x) = 24/5 - x/50 = 0 => x = 240 items.
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Correct Answer:
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