Straight Lines
Grade None

Question:

<p>A straight line through a fixed point (2, 3) intersects the coordinate axes at distinct points P and Q. If O is the origin and the rectangle OPRQ is completed, then the locus of R is</p>
<p style="display:inline">3x + 2y = xy</p>
<p style="display:inline">2x + 3y = xy</p>
<p style="display:inline">3x + 2y = 6xy</p>
<p style="display:inline">3x + 2y = 6</p>

Step-by-Step Solution

Key Concept: Relate the coordinates of vertex R to the intercepts of the line and use the given fixed point to establish the locus equation.
<p><img alt="" data-imgur-src="7F1e0KR.png" src="https://media-mycbseguide.s3.amazonaws.com/images/imgur/7F1e0KR.png" style="width: 200px; height: 117px;" /><br /> Equation of line PQ is <span class="math-tex">\(\frac{x}{\alpha}+\frac{y}{\beta}=1\)</span><br /> Since this line is passes through fixed point (2, 3).<br /> <span class="math-tex">\(\therefore \quad \frac{2}{\alpha}+\frac{3}{\beta}=1\)</span><br /> <span class="math-tex">\(\therefore\)</span>&nbsp;Locus of R is&nbsp;<span class="math-tex">\(2 \beta+3 \alpha=\alpha \beta\)</span><br /> i.e. 2y + 3x = xy&nbsp;<span class="math-tex">\(\Rightarrow\)</span>&nbsp;3x + 2y = xy</p>
Correct Answer: A

Master Straight Lines with Mathbee

Practice this topic under real exam conditions with strict timers, or ask our AI Mentor to explain the concepts step-by-step.

Start Practicing for Free