The area of circle circumscribing $x = \frac{-3h}{2}$ is:
Step-by-Step Solution
Key Concept: The circumcircle of a triangle formed by a point and two tangent points has its diameter determined by the angle subtended at the radical center.
Step 1: Identify the diameter of the circumcircle.
The problem statement indicates that for the circumcircle of $\triangle TAB$, the segment $TC_3$ serves as its diameter.
Step 2: Calculate the length of the diameter $TC_3$.
The length of the diameter $TC_3$ is given by the formula $TC_3 = \frac{TA}{\cos\left(\frac{\theta_1 + \theta_2}{2}\right)}$.
Substituting the given values $TA = 4$ and $\cos\left(\frac{\theta_1 + \theta_2}{2}\right) = \frac{1}{\sqrt{5}}$:
$$TC_3 = \frac{4}{\frac{1}{\sqrt{5}}} = 4\sqrt{5}$$
Step 3: Determine the radius of the circumcircle.
The radius $R$ of the circumcircle is half of its diameter.
$$R = \frac{TC_3}{2} = \frac{4\sqrt{5}}{2} = 2\sqrt{5}$$
Step 4: Calculate the area of the circumcircle.
The area of a circle is given by the formula $A = \pi R^2$.
Substituting the calculated radius $R = 2\sqrt{5}$:
$$A = \pi \left(2\sqrt{5}\right)^2 = \pi (4 \times 5) = 20\pi$$
Step 5: State the final answer.
The area of the circle is $20\pi$. This matches Option 2.
Correct Answer: 2