Three Dimensional Geometry
Xam Idea
CBSE
Grade 12
Question:
Find shortest distance between lines $\dfrac{x-1}{1} = \dfrac{y-2}{-1} = \dfrac{z-1}{1}$ and $\dfrac{x-2}{2} = \dfrac{y+1}{1} = \dfrac{z+1}{2}$.
Step-by-Step Solution
Key Concept: d = 3/\sqrt{2}.
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Correct Answer:
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