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Application of Derivatives
RS Aggarwal
CBSE
Grade 12

Question:

A particle moves along the curve $6y = x^3 + 2$. Find the points on the curve at which the y-coordinate is changing 8 times as fast as the x-coordinate.

Step-by-Step Solution

Key Concept: 6 dy/dt = 3x^2 dx/dt => 6(8 dx/dt) = 3x^2 dx/dt => x^2 = 16 => x = pm 4. Points (4, 11) and (-4, -31/3).
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Correct Answer:
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