Probability
NCERT Class 12
CBSE
Grade 12
Question:
If $P(A) = \dfrac{1}{3}, P(B) = \dfrac{1}{4}$ and $A, B$ are mutually exclusive, then $P(A \cap B)$ is:
(a) $0$
(b) $\dfrac{1}{12}$
(c) $\dfrac{7}{12}$
(d) $\dfrac{1}{7}$
Step-by-Step Solution
Mutually exclusive events $\Rightarrow P(A \cap B) = 0$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting 0: 1.0 Mark
Correct Answer: $0$
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