Vector Algebra
RS Aggarwal
CBSE
Grade 12
Question:
If $\vec{a}, \vec{b}, \vec{c}$ are mutually perpendicular unit vectors, show that $|\vec{a} + \vec{b} + \vec{c}| = \sqrt{3}$.
Step-by-Step Solution
Key Concept: |a+b+c|^2 = |a|^2 + |b|^2 + |c|^2 + 0 = 3 => \sqrt{3}.
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Correct Answer:
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