Application of Derivatives
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
The absolute maximum value of $y = x^3 - 3x$ on $[0, 2]$ is:
(a) $2$
(b) $0$
(c) $1$
(d) $-2$
Step-by-Step Solution
Critical points x=1. f(0)=0, f(1)=-2, f(2)=2. Max is 2. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting $2$: 1.0 Mark
Correct Answer: $2$
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