Inverse Trigonometric Functions
NCERT Class 12
CBSE
Grade 12
Question:
Find the value of $\tan^{-1}(\sqrt{3}) - \cot^{-1}(-\sqrt{3})$.
Step-by-Step Solution
$\tan^{-1}(\sqrt{3}) = \pi/3$ and $\cot^{-1}(-\sqrt{3}) = 5\pi/6$. [1.0 Mark]
Difference $= \pi/3 - 5\pi/6 = -\pi/2$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Finding individual terms $\pi/3$ and $5\pi/6$: 1.0 Mark
Evaluating difference $= -\pi/2$: 1.0 Mark
Correct Answer:
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