Question:

5 girls and 7 boys seated at a round table so no two girls sit together. Number of ways is

720

$126(5!)^2$

$7(360)^2$

$7(720)^2$

Step-by-Step Solution

Key Concept: Fix 7 boys in circle: $(7-1)!=6!$ ways. Place 5 girls in 7 gaps: $\binom{7}{5}\times5!$ ways.

$126(5!)^2$.

Correct Answer: 2