Probability Question - CBSE

Question

If $P(A) = \dfrac{7}{13}, P(B) = \dfrac{9}{13}$ and $P(A \cap B) = \dfrac{4}{13}$, then $P(A|B)$ is:
(a) $\dfrac{4}{9}$
(b) $\dfrac{4}{7}$
(c) $\dfrac{9}{13}$
(d) $\dfrac{7}{9}$

Accepted Answer

$P(A|B) = \dfrac{P(A \cap B)}{P(B)} = \dfrac{4/13}{9/13} = \dfrac{4}{9}$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Evaluating $P(A|B) = 4/9$: 1.0 Mark

Question:

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