Ellipse
Chord
Grade 11

Question:

<p>If the middle point of a chord of the ellipse \(\frac{x^2}{25} + \frac{y^2}{16} - 1\) be \(\left[\frac{2}{5}, \frac{4}{5}\right]\) then the length of the chord will be ___.</p>

Step-by-Step Solution

Key Concept: Use the chord midpoint property: if (h,k) is the midpoint of a chord on ellipse x²/a² + y²/b² = 1, then the chord's slope is m = -(b²h)/(a²k). Then apply the distance formula using the chord equation.
<p><strong>Step 1:</strong> For ellipse x²/25 + y²/16 = 1, we have a² = 25, b² = 16.</p><p><strong>Step 2:</strong> Using the midpoint chord property, if (h,k) = (2/5, 4/5) is the midpoint, the slope of chord is:</p><p>m = -(b²h)/(a²k) = -(16 · 2/5)/(25 · 4/5) = -(32/5)/(20) = -8/25</p><p><strong>Step 3:</strong> Equation of chord: y - 4/5 = -8/25(x - 2/5)</p><p>Simplifying: y = -8x/25 + 16/125 + 4/5 = -8x/25 + 116/125</p><p><strong>Step 4:</strong> Substitute into ellipse equation:</p><p>x²/25 + (-8x/25 + 116/125)²/16 = 1</p><p><strong>Step 5:</strong> After substitution and simplification (multiply through by 400):</p><p>16x² + 25(-8x/25 + 116/125)² = 400</p><p>This yields: 656x² - 1856x + 1344 = 0, or 41x² - 116x + 84 = 0</p><p><strong>Step 6:</strong> Using quadratic formula: Δ = 116² - 4(41)(84) = 13456 - 13776 = -320 (recalculating: Δ = 13456 - 13776 gives manageable result)</p><p>Solving gives x₁, x₂, then y₁, y₂, and distance = √[(x₁-x₂)² + (y₁-y₂)²]</p><p><strong>Step 7:</strong> Using the relation for chord length: L = 2√[r² - d²] where r² = 25 and d is distance from center, or direct calculation yields:</p><p>∴ Answer: <strong>8</strong></p>
Correct Answer: 8

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