Inverse Trigonometric Functions Question - CBSE

Question

Evaluate: $	an^{-1}(1) + \cos^{-1}\left(-\dfrac{1}{2}ight) + \sin^{-1}\left(-\dfrac{1}{2}ight)$.

Accepted Answer

$ an^{-1}(1) = \pi/4$. [0.5 Mark]
$\cos^{-1}(-1/2) + \sin^{-1}(-1/2) = \pi/2$. [1.0 Mark]
Total $= \pi/4 + \pi/2 = 3\pi/4$. [0.5 Mark]

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🎯 Official CBSE Marking Scheme:
Evaluating $ an^{-1}(1) = \pi/4$: 0.5 Mark
Applying identity $\cos^{-1}x + \sin^{-1}x = \pi/2$: 1.0 Mark
Evaluating final sum $= 3\pi/4$: 0.5 Mark

Question:

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