The probability that the birthdays of six different persons will fall in exactly two calendar months
Step-by-Step Solution
Key Concept: Choose 2 months, then distribute 6 birthdays in exactly those 2 months
$P=\frac{\binom{12}{2}(2^6-2)}{12^6}=\frac{66\cdot62}{12^6}=\frac{4092}{12^6}=\frac{341}{12^5}$.
Correct Answer: 3